3x+4^2=7(3x+4)

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Solution for 3x+4^2=7(3x+4) equation: 



3x+4^2=7(3x+4)

We move all terms to the left:

3x+4^2-(7(3x+4))=0

We add all the numbers together, and all the variables

3x-(7(3x+4))+16=0



We calculate terms in parentheses: -(7(3x+4)), so:

7(3x+4)

We multiply parentheses

21x+28

Back to the equation:

-(21x+28)



We get rid of parentheses

3x-21x-28+16=0

We add all the numbers together, and all the variables

-18x-12=0

We move all terms containing x to the left, all other terms to the right

-18x=12

x=12/-18

x=-2/3

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